The solution of differential equation d y d x +y x=2 x+x^ 2 x, y(0)=0 is,

Mathematics · JEE Main · NTA ExamsDifferential Equations

The solution of differential equation \(\frac{d y}{d x}+y \cot x=2 x+x^{2} \cot x, y(0)=0\) is,
  1. \(x^{2}=y\)
  2. \(y=x+c\)
  3. \(x^{2}=y^{2}+c\)
  4. None of these

Answer

(A) x^ 2 =y

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