The solution of differential equation d y d x +y x=2 x+x^ 2 x, y(0)=0 is,
Mathematics · JEE Main · NTA Exams — Differential Equations
The solution of differential equation \(\frac{d y}{d x}+y \cot x=2 x+x^{2} \cot x, y(0)=0\) is,
- \(x^{2}=y\)
- \(y=x+c\)
- \(x^{2}=y^{2}+c\)
- None of these
Answer
(A) x^ 2 =y
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