If y(t) is a solution of the differential equation (1+t) d y d t -t y=1 and y(0)=-1 …
Mathematics · JEE Main · NTA Exams — Differential Equations
If y(t) is a solution of the differential equation \((1+t) \frac{d y}{d t}-t y=1\) and \(y(0)=-1\), then y(1) is equal to
- \(-\frac{1}{2}\)
- \(e+\frac{1}{2}\)
- \(e-\frac{1}{2}\)
- \(\frac{1}{2}\)
Answer
(C) e- 1 2
Sign up free on Edukali to view the step-by-step worked solution and practice thousands of similar questions.
Related practice questions
- The degree of the differential equation corresponding to the family of curves y = a (x + a) 2 , where a is an…
- The solution of d y d x = e^ x ( ^ 2 x+ 2 x ) y(2 y+1) is-
- The solution of the equation x^ 2 d^ 2 y d x^ 2 = x when x =1_ 1 y = 0 and d y d x =-1 is,
- The differential equation d y d x = 1-y^ 2 y determines a family of circles with
- The solution of the equation (y-x d y d x ) ( d y d x -1 )= d y d x is,
- The equation of the curve for which the tangent at P (x, y) cuts the y – axis at (0, y 3 ) is
- The general solution of the differential equation y d x+ (1+x^ 2 ) ^ -1 x d y=0 is,
- The solution of differential equation (x^ 2 -y x^ 2 ) d y+ [y^ 2 +x^ 2 y^ 2 ) d x=0 is,
More Differential Equations questions · Browse all practice questions