The solution of the equation x^ 2 d^ 2 y d x^ 2 = x when x =1_ 1 y = 0 and d y d x =-1 is,

Mathematics · JEE Main · NTA ExamsDifferential Equations

The solution of the equation \(x^{2} \frac{d^{2} y}{d x^{2}}=\log x\) when \(\mathbf{x}=1_{1} \mathbf{y}=\mathbf{0}\) and \(\frac{d y}{d x}=-1\) is,
  1. \(\frac{1}{2}(\log x)^{2}+\log x\)
  2. \(\frac{1}{2}(\log x)^{2}-\log x\)
  3. \(-\frac{1}{2}(\log x)^{2}+\log x\)
  4. \(-\frac{1}{2}(\log x)^{2}-\log x\)

Answer

(D) - 1 2 ( x)^ 2 - x

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