The degree of the differential equation corresponding to the family of curves y=a(x+a)^ 2…
Mathematics · JEE Main · NTA Exams — Differential Equations
The degree of the differential equation corresponding to the family of curves \(y=a(x+a)^{2}\), where a is an arbitrary constant, is
- 1
- 2
- 3
- None of these
Answer
(C) 3
Sign up free on Edukali to view the step-by-step worked solution and practice thousands of similar questions.
Related practice questions
- Let y = y(x) be the solution of the differential equation, x d y d x +y=x _ e x,(x>1) . If 2 y(2)= _ e 4-1 …
- If y(x) is the solution of the differential equation d y d x + ( 2 x+1 x ) y=e^ -2 x , x>0 , where y(1)= 1 2…
- The solution of differential equation d y d x +y= 1+ x 1+ x , is
- If x d y d x -y x=6 x, (0<x< 2 ) and v ( 3 )=0 , then y ( 6 ) is equal to:
- The solution of Differential equation d y d x = x+2 y-3 2 x+y-3 is
- The order and degree of the differential equation (1+3 d y d x )^ 2 3 =4 d^ 3 y d x^ 3 is,
- The solution of the equation x^ 2 d^ 2 y d x^ 2 = x when x =1_ 1 y = 0 and d y d x =-1 is,
- The solution of the differential equation d y d x =1+x+y+x y is,
More Differential Equations questions · Browse all practice questions