The solution of Differential equation d y d x = x+2 y-3 2 x+y-3 is
Mathematics · JEE Main · NTA Exams — Differential Equations
The solution of Differential equation \(\frac{d y}{d x}=\frac{x+2 y-3}{2 x+y-3}\) is
- \[\frac{\left(1+\frac{y-1}{x-1}\right)^{1 / 2}}{\left(1-\frac{y-1}{x-1}\right)^{3 / 2}}=C\]
- \[\frac{\left(1+\frac{y-1}{x-1}\right)^{1 / 2}}{(x-1)\left(1-\frac{y-1}{x-1}\right)^{3 / 2}}=C\]
- none of these
Answer
(D) none of these
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