If y(x) is the solution of the differential equation d y d x + ( 2 x+1 x ) y=e^ -2 x …

Mathematics · JEE Main · NTA ExamsDifferential Equations

If y(x) is the solution of the differential equation \(\frac{d y}{d x}+\left(\frac{2 x+1}{x}\right) y=e^{-2 x}, x>0\), where \(y(1)=\frac{1}{2} e^{-2}\), then:
  1. \(y\left(\operatorname{lgg}_{e} 2\right)=\log _{e} 4\)
  2. y(x) is decreasing in (0, 1)
  3. \(y\left(\log _{e} 2\right)=\frac{\log _{e} 2}{4}\)
  4. y(x) is decreasing in \(\left(\frac{1}{2}, 1\right)\)

Answer

(D) y(x) is decreasing in ( 1 2 , 1 )

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