The solution of the differential equation d y d x =(3 x+y-1)^ 2 is,

Mathematics · JEE Main · NTA Exams — Differential Equations

1. \(\frac{1}{\sqrt{3}} \tan ^{-1} \frac{(3 x+y-1)}{3}=x+c\)
2. \(\frac{1}{\sqrt{3}} \tan ^{-1} \frac{(3 x+y-1)}{\sqrt{3}}=x+c\)
3. \(\sqrt{3} \tan ^{-1}(3 x+y-1)=3 x+c\)
4. None of these

Answer

(B) 1 3 ^ -1 (3 x+y-1) 3 =x+c

Sign up free on Edukali to view the step-by-step worked solution and practice thousands of similar questions.

Related practice questions

• Solution of the differential equation y (2 x^ 4 +y ) d y d x = (1-4 x y^ 2 ) x^ 2 is given by :
• The solution of differential equation (x^ 2 -y x^ 2 ) d y+ [y^ 2 +x^ 2 y^ 2 ) d x=0 is,
• The solution of differential equation dy dx – y tan x = – y 2 sec x is :
• A solution of the differential equation ( d y d x )^ 2 -x d y d x +y=0 is,
• The solution of (x 1+ y ^ 2 )dx + (y 1+x^ 2 )dy = 0 is -
• The solution of dy dx = 1 +x + y + xy is
• The solution of the equation d y d x = (1+x) y (y-1) x is :
• If d y d x =y+3>0 and y(0)=2 , then y( 2) is equal to

More Differential Equations questions · Browse all practice questions