The solution of dy dx = 1 +x + y + xy is

Mathematics · JEE Main · NTA Exams — Differential Equations

1. log (1 – y) = x + \(\frac{x^{3}}{2}\) + C
2. log (1 + y) = x + \(\frac{x^{2}}{2}\) + C
3. log (1 + y) = x – \(\frac{x^{2}}{2}\) – C
4. none of these

Answer

(B) log (1 + y) = x + x^ 2 2 + C

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