A curve passes through the point (0, 1) and the gradient at (x, y) on it is y (xy – 1)…
Mathematics · JEE Main · NTA Exams — Differential Equations
A curve passes through the point (0, 1) and the gradient at (x, y) on it is y (xy – 1). The equation of the curve is
- y (x – 1) = 1
- y (x + 1) = 1
- x (y + 1) = 1
- x (y – 1) = 1
Answer
(B) y (x + 1) = 1
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