The degree of the differential equation [1+ ( d y d x )^ 2 ]^ 5 3 = d^ 2 y d x^ 2 is :
Mathematics · JEE Main · NTA Exams — Differential Equations
The degree of the differential equation \[\left[1+\left(\frac{d y}{d x}\right)^{2}\right]^{\frac{5}{3}}=\frac{d^{2} y}{d x^{2}}\] is :
- 1
- 5
- \(\frac{10}{3}\)
- 3
Answer
(D) 3
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