The solution of d y d x = e^ x ( ^ 2 x+ 2 x ) y(2 y+1) is-
Mathematics · JEE Main · NTA Exams — Differential Equations
The solution of \(\frac{d y}{d x}=\frac{e^{x}\left(\sin ^{2} x+\sin 2 x\right)}{y(2 \log y+1)}\)is-
- y2 (log y) – ex sin2 x + c = 0
- y2 (log y) – ex cos2 x + c = 0
- y2 (log y) + ex cos2 x + c = 0
- None of these
Answer
(A) y 2 (log y) – e x sin 2 x + c = 0
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