The solution of the differential equation (x+2 y^ 3 ) d y d x =y y(z)=1 is,
Mathematics · JEE Main · NTA Exams — Differential Equations
The solution of the differential equation \(\left(x+2 y^{3}\right) \frac{d y}{d x}=y \cdot y(z)=1\) is,
- \(x=y^{2}+y\)
- \(x^{2}=y^{3}+y^{2}\)
- \(x=y^{3}+y\)
- None of these
Answer
(C) x=y^ 3 +y
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