The solution of the differential equation (x+2 y^ 3 ) d y d x =y y(z)=1 is,

Mathematics · JEE Main · NTA ExamsDifferential Equations

The solution of the differential equation \(\left(x+2 y^{3}\right) \frac{d y}{d x}=y \cdot y(z)=1\) is,
  1. \(x=y^{2}+y\)
  2. \(x^{2}=y^{3}+y^{2}\)
  3. \(x=y^{3}+y\)
  4. None of these

Answer

(C) x=y^ 3 +y

Sign up free on Edukali to view the step-by-step worked solution and practice thousands of similar questions.

Related practice questions

More Differential Equations questions · Browse all practice questions