The differential equation of all circles passing through the origin and having their…
Mathematics · JEE Main · NTA Exams — Differential Equations
The differential equation of all circles passing through the origin and having their centres on the x-axis is
- \(x^{2}=y^{2}+x y \frac{d y}{d x}\)
- \(x^{2}=y^{2}+3 x y \frac{d y}{d x}\)
- \(y^{2}=x^{2}+2 x y \frac{d y}{d x}\)
- \(y^{2}=x^{2}-2 x y \frac{d y}{d x}\)
Answer
(C) y^ 2 =x^ 2 +2 x y d y d x
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