The differential equation of all circles passing through the origin and having their…

Mathematics · JEE Main · NTA ExamsDifferential Equations

The differential equation of all circles passing through the origin and having their centres on the x-axis is
  1. \(x^{2}=y^{2}+x y \frac{d y}{d x}\)
  2. \(x^{2}=y^{2}+3 x y \frac{d y}{d x}\)
  3. \(y^{2}=x^{2}+2 x y \frac{d y}{d x}\)
  4. \(y^{2}=x^{2}-2 x y \frac{d y}{d x}\)

Answer

(C) y^ 2 =x^ 2 +2 x y d y d x

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