The general solution of the differential equation (1 + y 2 ) dx + (1 + x 2 ) dy = 0 is

Mathematics · JEE Main · NTA Exams — Differential Equations

1. x – y = C (1 – xy)
2. x – y = C (1 + xy)
3. x + y = C (1 – xy)
4. x + y = C (1 + xy)

Answer

(C) x + y = C (1 – xy)

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