The solution of y_ 1 -8 y_ 2 =0 satisfying y (0)= 1 8 , y _ 1 (0)=0 and Y _ 2 (0)=1 is :
Mathematics · JEE Main · NTA Exams — Differential Equations
The solution of \(y_{1}-8 y_{2}=0\) satisfying \(\mathrm{y}(0)=\frac{1}{8}, \mathrm{y}_{1}(0)=0\) and \(\mathrm{Y}_{2}(0)=1\) is :
- \(y=\frac{1}{8}\left(\frac{e^{3 x}}{8}+x-\frac{7}{8}\right)\)
- \(y=\frac{1}{8}\left(\frac{e^{3 x}}{8}-x+\frac{7}{8}\right)\)
- \(y=\frac{1}{6}\left(\frac{e^{5 x}}{6}+x-\frac{5}{8}\right)\)
- None of these
Answer
(D) None of these
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