A tangent to the curve y = f (x) cuts the line y = x at a point which is at a distance of…
Mathematics · JEE Main · NTA Exams — Differential Equations
A tangent to the curve y = f (x) cuts the line y = x at a point which is at a distance of 1 unit from y–axis. The equation of the curve is
- \(\frac{x-1}{y-1}=c\)
- \(\frac{x}{y}=c\)
- xy = c
- none of these
Answer
(A) x-1 y-1 =c
Sign up free on Edukali to view the step-by-step worked solution and practice thousands of similar questions.
Related practice questions
- The solution of the differential equation cos y log (sec x + tan x) dx = cos x log (sec y + tan y ) dy is
- The solution of (cosec x log y)dy + (x 2 y)dx=0 is -
- Solution of the differential equation cos x dy = y (sin x – y) dx, 0 < x < 2 , is
- The solution of the differential equation d y d x = y+x 2 y-x y is
- Let y = y(x) be the solution curve of the differential equation (y^ 2 -x ) d y d x =1 , satisfying y(0) = 1…
- If sin x is an integrating factor of the differential equation dy dx + Py = Q, then P can be
- The solution of the differential equation y d x+ [x+x^ 2 y ] d y=0 is,
- STATEMENT - 1 (Assertion): The elimination of four arbitrary constants in y= (c_ 1 +c_ 2 +c_ 3 e^ I_ 4 ) x…
More Differential Equations questions · Browse all practice questions