The solution of (cosec x log y)dy + (x 2 y)dx=0 is -

Mathematics · JEE Main · NTA Exams — Differential Equations

1. \(\frac{\log y}{2}\) + (2 – x²) cos x + 2 sin x = c
2. \(\left(\frac{\log y}{2}\right)^{2}\)+ (2 – x²) cos x + 2x sin x = c
3. \(\frac{(\log y)^{2}}{2}\) + (2 – x²) cos x + 2x sin x=c
4. None of these

Answer

(C) ( y)^ 2 2 + (2 – x 2 ) cos x + 2x sin x=c

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