Consider the differential equation y^ 2 d x+ (x- 1 y ) d y=0 . If y (1) = 1, then x is…

Mathematics · JEE Main · NTA Exams — Differential Equations

1. \(1-\frac{1}{y}+\frac{e^{1 / y}}{e}\)
2. \(4-\frac{2}{y}-\frac{e^{1 / y}}{e}\)
3. \(3-\frac{1}{y}+\frac{e^{1 / y}}{e}\)
4. \(1+\frac{1}{y}-\frac{e^{1 / y}}{e}\)

Answer

(D) 1+ 1 y - e^ 1 / y e

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