The solution of differential equation x 2 y dx – (x 3 + y 3 ) dy = 0 is
Mathematics · JEE Main · NTA Exams — Differential Equations
The solution of differential equation
x2 y dx – (x3 + y3) dy = 0 is
x2 y dx – (x3 + y3) dy = 0 is
- \(\frac{1}{3} \frac{x^{3}}{y^{3}}+\log y=C\)
- \(\frac{1}{3} \frac{x^{3}}{y^{3}}-\log y=C\)
- \(\frac{x^{3}}{y^{3}}+\log y=-C\)
- none of these
Answer
(B) 1 3 x^ 3 y^ 3 - y=C
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