The general solution of the differential equation y [x^ 2 y+e^ x ] d x-e^ x d y=0 is,

Mathematics · JEE Main · NTA Exams — Differential Equations

1. \(x^{3} y-3 e^{x}=C y\)
2. \(x^{3} y+3 e^{x}=6 y\)
3. \(y^{3} x-3 e^{y}=6 y\)
4. \(\mathrm{y}^{3} \mathrm{x}+3 \mathrm{e}^{\mathrm{y}}=\mathrm{Cy}\)

Answer

(B) x^ 3 y+3 e^ x =6 y

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