The solution of the differential equation y d x+ [x+x^ 2 y ] d y=0 is,

Mathematics · JEE Main · NTA Exams — Differential Equations

1. \(-\frac{1}{x y}=c\)
2. \(-\frac{1}{x y}+\log y=c\)
3. \(\frac{1}{x y}+\log y=c\)
4. \(\log y=6 x\)

Answer

(C) 1 x y + y=c

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