The solution of the differential equation d y d x =1+x+y+x y is,
Mathematics · JEE Main · NTA Exams — Differential Equations
The solution of the differential equation \(\frac{d y}{d x}=1+x+y+x y\) is,
- \(\log |1+y|=x+\frac{x^{2}}{2}+c\)
- \(\log |1-y|=x+\frac{x^{2}}{2}+c\)
- \(\log |1+y|=x-\frac{x^{2}}{2}+c\)
- None of these
Answer
(A) |1+y|=x+ x^ 2 2 +c
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