The solution of the differential equation d y d x =1+x+y+x y is,

Mathematics · JEE Main · NTA ExamsDifferential Equations

The solution of the differential equation \(\frac{d y}{d x}=1+x+y+x y\) is,
  1. \(\log |1+y|=x+\frac{x^{2}}{2}+c\)
  2. \(\log |1-y|=x+\frac{x^{2}}{2}+c\)
  3. \(\log |1+y|=x-\frac{x^{2}}{2}+c\)
  4. None of these

Answer

(A) |1+y|=x+ x^ 2 2 +c

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