The solution of the differential equation e^ -x (y+1) d y+ [ ^ 2 x- 2 x ] y d y=0 is,

Mathematics · JEE Main · NTA ExamsDifferential Equations

The solution of the differential equation \(e^{-x}(y+1) d y+\left[\cos ^{2} x-\sin 2 x\right] y d y=0\) is,
  1. \(y+\log y+e^{x} \cos ^{2} x=0\)
  2. \(\log (y+1)+e^{x} \cos ^{2} x=1\)
  3. \(y+\log y=e^{x} \cos ^{2} x\)
  4. \((y+1)+e^{x} \cos ^{2} x=2\)

Answer

(B) (y+1)+e^ x ^ 2 x=1

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