The solution of the differential equation e^ -x (y+1) d y+ [ ^ 2 x- 2 x ] y d y=0 is,
Mathematics · JEE Main · NTA Exams — Differential Equations
The solution of the differential equation \(e^{-x}(y+1) d y+\left[\cos ^{2} x-\sin 2 x\right] y d y=0\) is,
- \(y+\log y+e^{x} \cos ^{2} x=0\)
- \(\log (y+1)+e^{x} \cos ^{2} x=1\)
- \(y+\log y=e^{x} \cos ^{2} x\)
- \((y+1)+e^{x} \cos ^{2} x=2\)
Answer
(B) (y+1)+e^ x ^ 2 x=1
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