The solution of the equation d^ 2 y d x^ 2 =e^ -2 x is,

Mathematics · JEE Main · NTA Exams — Differential Equations

1. \(\frac{e^{-2 x}}{4}\)
2. \(\frac{e^{-2 x}}{4}+e x+\square\)
3. \(\frac{1}{4} e^{-2 x}+C x^{2}+\square\)
4. \(\frac{1}{4} e^{-4 x}+c x+\square\)

Answer

(B) e^ -2 x 4 +e x+

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