The solution of the differential equation y_ 1 1+x+y =x+y-1 is ,

Mathematics · JEE Main · NTA Exams — Differential Equations

1. \(2 \sqrt{1+x+y}+\frac{2}{3} \log |\sqrt{1+x+y}-1|\) \(-\frac{8}{3} \log |\sqrt{1+x+y}+z|=x+c\)
2. \(2 \sqrt{1+x+y}-\frac{2}{3} \log |\sqrt{1+x+y}-1|\)\(-\frac{8}{3} \log |\sqrt{1+x+y}+z|=x+c\)
3. \(\frac{2}{3} \log |\sqrt{1+x+y}-1|\)\(+\frac{8}{3} \log |\sqrt{1+x+y}+z|-x=0\)
4. None of these

Answer

(A) 2 1+x+y + 2 3 | 1+x+y -1| - 8 3 | 1+x+y +z|=x+c

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