The equation of a curve passing through (2, 7 2 ) and having gradient 1- 1 x^ 2 at (x, y)…
Mathematics · JEE Main · NTA Exams — Differential Equations
The equation of a curve passing through \(\left(2, \frac{7}{2}\right)\) and having gradient \(1-\frac{1}{x^{2}}\) at (x, y) is
- y = x2 + x + 1
- xy = x2 + x + 1
- xy = x + 1
- none of these
Answer
(B) xy = x 2 + x + 1
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