The solution of the differential equation xy d y d x = (1+y^ 2 ) (1+x+x^ 2 ) (1+x^ 2 ) is…
Mathematics · JEE Main · NTA Exams — Differential Equations
The solution of the differential equation
xy \(\frac{d y}{d x}=\frac{\left(1+y^{2}\right)\left(1+x+x^{2}\right)}{\left(1+x^{2}\right)}\) is -
xy \(\frac{d y}{d x}=\frac{\left(1+y^{2}\right)\left(1+x+x^{2}\right)}{\left(1+x^{2}\right)}\) is -
- \(\frac{1}{2}\)log (1 + y2) = log x – tan–1 x + c
- \(\frac{1}{2}\) log (1 + y2) = log x + tan–1x + c
- log (1 + y2) = log x – tan–1x + c
- log (1 + y2) = log x + tan–1 x + c
Answer
(B) 1 2 log (1 + y 2 ) = log x + tan –1 x + c
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