The slope of the tangent at (x, y) to a curve passing through (2, 1) is x^ 2 +y^ 2 2 x y…
Mathematics · JEE Main · NTA Exams — Differential Equations
The slope of the tangent at (x, y) to a curve passing through (2, 1) is \(\frac{x^{2}+y^{2}}{2 x y},\)then the equation of the curve is
- 2 (x2 – y2) = 3 x
- 2 (x2 – y2) = 6y
- x (x2 – y2) = 6
- x (x2 + y2) = 10
Answer
(A) 2 (x 2 – y 2 ) = 3 x
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