The solution of the differential equation x x^ 2 +y^ 2 d y= ( y x^ 2 +y^ 2 -1 ) dx is

Mathematics · JEE Main · NTA Exams — Differential Equations

1. y = x cot (c – x)
2. \(\cos ^{-1} \frac{y}{x}=(-x+c)\)
3. y = x tan (c – x)
4. \(\frac{y^{2}}{x^{2}}=x \tan (c-x)\)

Answer

(C) y = x tan (c – x)

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