The solution of differential equation 2 x^ 3 y d y+ [1-y^ 2 ) [x^ 2 y^ 2 +y^ 2 -1 ] d x=0
Mathematics · JEE Main · NTA Exams — Differential Equations
The solution of differential equation \(2 x^{3} y d y+\left[1-y^{2}\right)\left[x^{2} y^{2}+y^{2}-1\right] d x=0\)
- \(\mathbf{x}^{2} \mathbf{y}^{2}=(\mathbf{x}+1)\left(1-\mathbf{y}^{2}\right)\)
- \(\mathbf{x}^{2} \mathbf{y}^{2}=(\mathbf{x}+1)\left(1+\mathbf{y}^{2}\right)\)
- \(\mathbf{x}^{2} \mathbf{y}^{2}=(\mathbf{x}-1)\left(1-\mathbf{y}^{2}\right)\)
- none of these
Answer
(A) x ^ 2 y ^ 2 =( x +1) (1- y ^ 2 )
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