Solution of the differential equation y (2 x^ 4 +y ) d y d x = (1-4 x y^ 2 ) x^ 2 is…
Mathematics · JEE Main · NTA Exams — Differential Equations
Solution of the differential equation \(y\left(2 x^{4}+y\right) \frac{d y}{d x}=\left(1-4 x y^{2}\right) x^{2}\) is given by :
- \(3\left(x^{2} y\right)^{2}+y^{3}-x^{3}=c\)
- \(x y^{2}+\frac{y^{3}}{3}-\frac{x^{3}}{3}+c=0\)
- \(\frac{2}{5} y x^{5}+\frac{y^{3}}{3}=\frac{y^{3}}{3}-\frac{4 x y^{3}}{3}+c\)
- None of these
Answer
(A) 3 (x^ 2 y )^ 2 +y^ 3 -x^ 3 =c
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