The solution of the differential equation d y d x =y x-2 x_ 1
Mathematics · JEE Main · NTA Exams — Differential Equations
The solution of the differential equation \(\frac{d y}{d x}=y \tan x-2 \sin x_{1}\)
- \(y \sin x=[+\sin 2 x\)
- \(y \cos x=c+\frac{1}{2} \sin x\)
- \(y \cos x=C-\sin 2 x\)
- \(y \cos x=c+\frac{1}{2} \cos 2 x\)
Answer
(C) y x=C- 2 x
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