Let y = y(x) be the solution of the differential equation, x d y d x +y=x _ e x,(x>1) …
Mathematics · JEE Main · NTA Exams — Differential Equations
Let y = y(x) be the solution of the differential equation, \(x \frac{d y}{d x}+y=x \log _{e} x,(x>1)\). If \(2 y(2)=\log _{\mathrm{e}} 4-1\), then y(e) is equal to:
- \(-\frac{\mathbf{e}}{2}\)
- \(-\frac{e^{2}}{2}\)
- \(\frac{e^{2}}{4}\)
- \(\frac{e}{4}\)
Answer
(D) e 4
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