Let y=y(x) be the solution of the differential equation, (x^ 2 +1 )^ 2 d y d x +2 x (x^ 2…
Mathematics · JEE Main · NTA Exams — Differential Equations
Let \(y=y(x)\) be the solution of the differential equation, \(\left(x^{2}+1\right)^{2} \frac{d y}{d x}+2 x\left(x^{2}+1\right) y=1\) such that \(y(0)=0\). If \(\sqrt{a} y(1)=\frac{\pi}{32}\), then the value of 'a' is:
- \(\frac{1}{2}\)
- \(\frac{1}{4}\)
- \(\frac{1}{16}\)
- 1
Answer
(C) 1 16
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