The solution of the equation x^ 3 d y d x +4 x^ 2 tan y = e x sec y satisfying y (1) = 0…

Mathematics · JEE Main · NTA Exams — Differential Equations

1. tan y = (x – 2) e^x log 3
2. sin y = e^x (x – 1) x^–4
3. tan y = (x – 1) e^x x^–3
4. sin y = e^x (x – 1) x^–3

Answer

(B) sin y = e x (x – 1) x –4

Sign up free on Edukali to view the step-by-step worked solution and practice thousands of similar questions.

Related practice questions

• The general solution of the differential equation [2 x y -x] dy + y dx = 0 is
• The solution of y=x ( d y d x + ( d y d x )^ 3 ) , where p= d y d x is given by
• Let a solution y=y(x) of the differential equation x x^ 2 -1 d y-y y^ 2 -1 d x=0 satisfy y(2)= 2 3 …
• If a curve passes through the point (1, -2) and has slope of the tangent at any point (x, y) on it as x^ 2 -2…
• The solution of the differential equation d y d x = ^ 2 (x+y) is,
• If sin x is an integrating factor of the differential equation dy dx + Py = Q, then P can be
• The general solution of the differential equation y(x 2 y + e x ) dx – e x dy = 0 is
• If φ (x) is a differentiable function, then the solution of the differential equation d y+ y ^ (x)- (x) ^ (x)…

More Differential Equations questions · Browse all practice questions