The solution of (x 1+ y ^ 2 )dx + (y 1+x^ 2 )dy = 0 is -

Mathematics · JEE Main · NTA Exams — Differential Equations

1. \(\sqrt{1+x^{2}}+\sqrt{1+y^{2}}\) = c
2. \(\sqrt{1+x^{2}}-\sqrt{1+y^{2}}\) = c
3. (1 + x²)^3/2 + (1 + y²)^3/2 = c
4. None of these

Answer

(A) 1+x^ 2 + 1+y^ 2 = c

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