The general solution of the differential equation y d x+ (1+x^ 2 ) ^ -1 x d y=0 is,

Mathematics · JEE Main · NTA Exams — Differential Equations

1. \(y \tan ^{-1} x=c\)
2. \(\mathbf{x} \tan ^{-1} \mathbf{y}=\mathbf{c}\)
3. \(y+\tan ^{-1} x=0\)
4. \(\mathbf{x}+\tan ^{-1} \mathbf{y}=\mathbf{c}\)

Answer

(A) y ^ -1 x=c

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