Direction cosines of normal to the plane containing lines x=y=z and x -1= y -1= z -1 d…
Mathematics · JEE Main · NTA Exams — Three Dimensional Geometry
Direction cosines of normal to the plane containing lines \(x=y=z\) and \(\mathbf{x}-1=\mathbf{y}-1=\frac{\mathbf{z}-1}{\mathbf{d}}\) (where \(d E R-\{1\}\)}, are
- \(\left\{\frac{1}{\sqrt{2}},-\frac{1}{\sqrt{2}}, 0\right\}\)
- \(\left\{\frac{1}{\sqrt{2}}, 0, \frac{1}{\sqrt{2}}\right\}\)
- \(\left\{0,-\frac{1}{\sqrt{2}}, \frac{1}{\sqrt{2}}\right\}\)
- none of these
Answer
(C) 0,- 1 2 , 1 2
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