|( A + B )|^ 2 +|( A - B )|^ 2 equals

Mathematics · JEE Main · NTA ExamsThree Dimensional Geometry

\(|(\overrightarrow{\mathrm{A}}+\overrightarrow{\mathrm{B}})|^{2}+|(\overrightarrow{\mathrm{A}}-\overrightarrow{\mathrm{B}})|^{2}\) equals
  1. \(2\left(|\overrightarrow{\mathrm{~A}}|^{2}+|\overrightarrow{\mathrm{B}}|^{2}\right)\)
  2. \(4|\overrightarrow{\mathrm{~A}}| \cdot|\overrightarrow{\mathrm{B}}|\)
  3. \(|\overrightarrow{\mathrm{A}}|^{2}+|\overrightarrow{\mathrm{B}}|^{2}\)
  4. none of these

Answer

(A) 2 (| ~A |^ 2 +| B |^ 2 )

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