|( A + B )|^ 2 +|( A - B )|^ 2 equals
Mathematics · JEE Main · NTA Exams — Three Dimensional Geometry
\(|(\overrightarrow{\mathrm{A}}+\overrightarrow{\mathrm{B}})|^{2}+|(\overrightarrow{\mathrm{A}}-\overrightarrow{\mathrm{B}})|^{2}\) equals
- \(2\left(|\overrightarrow{\mathrm{~A}}|^{2}+|\overrightarrow{\mathrm{B}}|^{2}\right)\)
- \(4|\overrightarrow{\mathrm{~A}}| \cdot|\overrightarrow{\mathrm{B}}|\)
- \(|\overrightarrow{\mathrm{A}}|^{2}+|\overrightarrow{\mathrm{B}}|^{2}\)
- none of these
Answer
(A) 2 (| ~A |^ 2 +| B |^ 2 )
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