The equation of the plane passing through the points (3, 2, 2) and (1, 0 –1) and parallel…
Mathematics · JEE Main · NTA Exams — Three Dimensional Geometry
The equation of the plane passing through the points
(3, 2, 2) and (1, 0 –1) and parallel to the line \(\frac{x-1}{2}=\frac{y-1}{-2}=\frac{z-2}{3}\), is
(3, 2, 2) and (1, 0 –1) and parallel to the line \(\frac{x-1}{2}=\frac{y-1}{-2}=\frac{z-2}{3}\), is
- 4x – y – 2z + 6 = 0
- 4x – y + 2z + 6 = 0
- 4x – y – 2z – 6 = 0
- 3x – 2z – 5 = 0
Answer
(D) 3x – 2z – 5 = 0
Sign up free on Edukali to view the step-by-step worked solution and practice thousands of similar questions.
Related practice questions
- If ( a b ) c = a ( b c ) , where a , b , c are any three vectors such that ≠ 0, b c ≠ 0, then a and c are
- The plane ax + by + cz = 1 meets the co-ordinate axes in A, B and C. The centroid of the triangle is :
- Equation of the line passing through (1,1,1) and perpendicular to 2 x+3 y+z+5=0 is :
- Two non zero vectors a and b will be parallel, if
- Image of the point P with position vector 7 i - j +2 k in the line whose vector equation is, r =9 i +5 j +5 k…
- The distance between the parallel planes a x+b y+c z+d=0 and a x+b y+c z+d^ =0 is :
- If a line makes an angle of 4 with the positive directions of each of x - axis and y^ - axis, then the angle…
- If | a b |= a ~b then angle between a and b is
More Three Dimensional Geometry questions · Browse all practice questions