Equation of the line passing through (1,1,1) and perpendicular to 2 x+3 y+z+5=0 is :

Mathematics · JEE Main · NTA Exams — Three Dimensional Geometry

1. \(\frac{x-1}{1}=\frac{y-1}{3}=\frac{z-1}{2}\)
2. \(\frac{x-1}{3}=\frac{y-1}{3}=\frac{z-1}{1}\)
3. \(\frac{x-1}{2}=\frac{y-1}{3}=\frac{z-1}{1}\)
4. \(\frac{x-1}{-1}=\frac{y-1}{1}=\frac{z-1}{1}\)

Answer

(C) x-1 2 = y-1 3 = z-1 1

Sign up free on Edukali to view the step-by-step worked solution and practice thousands of similar questions.

Related practice questions

• The point at which the line joining the points (2, –3, 1) & (3, –4, –5) intersects the plane 2x + y + z = 7…
• The area of the quadrilateral ABCD, where A(0, 4, 1), B(2, 3, –1), C(4, 5, 0) and D(2, 6, 2), is equal to
• The vector c , directed along the internal bisector of the angle between the vectors, a =7 i -4 j -4 k and b…
• The angle between the lines 2x = 3y = – z and 6x = – y = – 4z is
• The direction cosines of a line whose equation is x-1 2 = y+3 4 = z-2 -3 , are
• If a and b are vectors of equal magnitude 2 and α be the angle between them, then magnitude of a + b will be…
• If | a b |= a ~b then angle between a and b is
• The unit vector perpendicular to vectors i + j and j + k is

More Three Dimensional Geometry questions · Browse all practice questions