The direction cosines of a line whose equation is x-1 2 = y+3 4 = z-2 -3 , are
Mathematics · JEE Main · NTA Exams — Three Dimensional Geometry
The direction cosines of a line whose equation is \(\frac{x-1}{2}=\frac{y+3}{4}=\frac{z-2}{-3}\), are
- \(\frac{1}{\sqrt{14}}, \frac{-3}{\sqrt{14}}, \frac{2}{\sqrt{14}}\)
- \(\frac{2}{\sqrt{29}}, \frac{4}{\sqrt{29}}, \frac{-3}{\sqrt{29}}\)
- \(\frac{1}{\sqrt{29}}, \frac{-3}{\sqrt{29}}, \frac{2}{\sqrt{29}}\)
- \(2,4,-3\)
Answer
(B) 2 29 , 4 29 , -3 29
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