The point of intersection of lines, x -4 5 = y -1 2 = z 1 x -1 2 = y -2 3 = z -3 4 is :
Mathematics · JEE Main · NTA Exams — Three Dimensional Geometry
The point of intersection of lines,
\(\frac{\mathrm{x}-4}{5}=\frac{\mathrm{y}-1}{2}=\frac{\mathrm{z}}{1} \& \frac{\mathrm{x}-1}{2}=\frac{\mathrm{y}-2}{3}=\frac{\mathrm{z}-3}{4}\) is :
\(\frac{\mathrm{x}-4}{5}=\frac{\mathrm{y}-1}{2}=\frac{\mathrm{z}}{1} \& \frac{\mathrm{x}-1}{2}=\frac{\mathrm{y}-2}{3}=\frac{\mathrm{z}-3}{4}\) is :
- (–1, –1, –1)
- (–1, –1, 1)
- (1, –1, –1)
- (–1, 1, –1)
Answer
(A) (–1, –1, –1)
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