The equation of the plane through the intersection of the planes ax + by + cz + d = 0 and…

Mathematics · JEE Main · NTA Exams — Three Dimensional Geometry

1. (bl – am) y + (cl – an) z + dl – ap = 0
2. (am – bl) x + (mc – bn) z + md – bp = 0
3. (na – cl) x + (bn – cm) y + nd – cp = 0
4. none of these

Answer

(A) (b l – am) y + (c l – an) z + d l – ap = 0

Sign up free on Edukali to view the step-by-step worked solution and practice thousands of similar questions.

Related practice questions

• If a and b are two vectors, then -
• The points with position vectors 3 i -4 j -4 k , 2 i - j + k and i -3 j -5 k form
• The angle between the line x-2 a = y-2 b = z-2 c and the plane ax + by + cz + 6 = 0 is
• Consider points A, B, C and D with position vectors 7 i -4 j +7 k , i -6 j +10 k , - i -3 j +4 k and 5 i - j…
• If position vectors of A, B, C, D are respectively 2 i +3 j +5 k , i +2 j +3 k ,-5 i +4 j -2 k and i +10 j…
• The line, x-2 3 = y-3 4 = z-4 5 is parallel to the plane :
• Given below are two statements. STATEMENT - 1: If 'a' is an integer, then the straight lines r = i +2 j +3 k…
• The distance of point of intersection of lines x-4 1 = y+3 -4 = z+1 7 and x-1 2 = y+1 -3 = z+10 8 from the…

More Three Dimensional Geometry questions · Browse all practice questions