The angle between the line x-2 a = y-2 b = z-2 c and the plane ax + by + cz + 6 = 0 is

Mathematics · JEE Main · NTA Exams — Three Dimensional Geometry

1. \(\sin ^{-1} \frac{1}{\sqrt{a^{2}+b^{2}+c^{2}}}\)
2. 45º
3. 60º
4. 90º

Answer

(D) 90º

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