The angle between the line, x+1 3 = y-1 2 = z-2 4 and the plane, 2x + y – 3z + 4 = 0, is :
Mathematics · JEE Main · NTA Exams — Three Dimensional Geometry
The angle between the line, \(\frac{x+1}{3}=\frac{y-1}{2}=\frac{z-2}{4}\)and the plane, 2x + y – 3z + 4 = 0, is :
- \(\sin ^{-1}\left(\frac{4}{\sqrt{406}}\right)\)
- \[\sin ^{-1}\left(\frac{14}{\sqrt{406}}\right)\]
- \(\sin ^{-1}\left(\frac{4}{14 \sqrt{29}}\right)\)
- None of these
Answer
(A) ^ -1 ( 4 406 )
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