If the given planes, ax + by + cz + d = 0 and a´x + b´y + c´z + d´ = 0 be mutually…
Mathematics · JEE Main · NTA Exams — Three Dimensional Geometry
If the given planes, ax + by + cz + d = 0 and
a´x + b´y + c´z + d´ = 0 be mutually perpendicular, then:
a´x + b´y + c´z + d´ = 0 be mutually perpendicular, then:
- \(\frac{\mathrm{a}}{\mathrm{a}^{\prime}}=\frac{\mathrm{b}}{\mathrm{~b}^{\prime}}=\frac{\mathrm{c}}{\mathrm{c}^{\prime}}\)
- \(\frac{\mathrm{a}}{\mathrm{a}^{\prime}}+\frac{\mathrm{b}}{\mathrm{~b}^{\prime}}+\frac{\mathrm{c}}{\mathrm{c}^{\prime}}=0\)
- aa´ + bb´ + cc´ + dd´ = 0
- aa´ + bb´ + cc´ = 0
Answer
(D) aa´ + bb´ + cc´ = 0
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