If (2,3,5) is one end of a diameter of the sphere x^ 2 +y^ 2 +z^ 2 -6 x-12 y-2 z+30=0 …
Mathematics · JEE Main · NTA Exams — Three Dimensional Geometry
If \((2,3,5)\) is one end of a diameter of the sphere \(x^{2}+y^{2}+z^{2}-6 x-12 y-2 z+30=0\), then the coordinates of the other end of diameter are
- (4, 9, -3)
- (4, -3, 3)
- (4, 3, 5)
- (4, 3, -3)
Answer
(A) (4, 9, -3)
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