The vector equation of the plane is r [2 i -3 j +6 k ]=13 ; where 2 i -3 j +6 k is normal…
Mathematics · JEE Main · NTA Exams — Three Dimensional Geometry
The vector equation of the plane is \(\vec{r} \cdot[2 \hat{i}-3 \hat{j}+6 \hat{k}]=13 ; \text { where } 2 \hat{i}-3 \hat{j}+6 \hat{k}\) is normal to the plane. Find the length of the ⊥ from the origin to the plane
- \(\frac{14}{7}\)
- \(\frac{13}{6}\)
- \(\frac{13}{7}\)
- None of these
Answer
(C) 13 7
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