The point of intersection of the line x 1 = y-1 2 = z+2 3 and the plane, 2x + 3y + z = 0…
Mathematics · JEE Main · NTA Exams — Three Dimensional Geometry
The point of intersection of the line \(\frac{x}{1}=\frac{y-1}{2}=\frac{z+2}{3}\) and the plane, 2x + 3y + z = 0, is :
- (0, 1, –2)
- (1, 2, 3)
- (–1, 9, –25)
- \(\left(\frac{-1}{11}, \frac{9}{11}, \frac{-25}{11}\right)\)
Answer
(D) ( -1 11 , 9 11 , -25 11 )
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